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horsena [70]
3 years ago
9

SOMEONE PLEASE HELP!! i’ll give brainliest

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

y = 1/2 x + 3/2

Step-by-step explanation:

We need to start by finding the slope of the given line, since a line parallel to it will have the same slope. Then we need to solve for y in the given equation;

- 2 x + 4 y = 8

add 2x to both sides

4 y = 2 x + 8

divide both sides by 4 to isolate y

y = 1/2 x + 2

Then, the slope we are looking for is "1/2"

Now we write the equation of the parallel line we are trying to find, in "point slope form", using the point (-5, -1) we want to have on the line:

y = m (x - x1) + y1

replacing m with our slope 1/2, x1 with -5, and y1 with -1:

y = 1/2 (x - -5) + (-1)

y = 1/2 x + 5/2 - 1

y = 1/2 x + 3/2

lys-0071 [83]3 years ago
6 0
-2x + 4y = 8
4y = 2x + 8
y = 1/2x + 2

m = 1/2

y + 1 = 1/2(x + 5)

y = 1/2x + 3/2
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And he runs the same number of miles ask every day. His total distance run for one week is less than 60 miles. Which any quality
stiv31 [10]

Answer:

around 8 or 8.5 miles a day for 7 days

Step-by-step explanation:

60 divided 7 equals 8.5

3 0
3 years ago
(Lots of points)PLEASE HELP ME Due today at 8:59 in Texas
IceJOKER [234]

Answer:

6.) So 8 of 24 hours is 1/3. So the percent of his time used was <u><em>33.33333 . . %</em></u> (etc)

7.) The easiest way to figure out a percentage is dividing it. So if it was 30 hit out of 75 people, then divide 30 by 75. So <u><em>40%</em></u> of them got hit.

Hope that helps

6 0
2 years ago
Question 19 of 25 -
zubka84 [21]
X+14 because (look at the picture)
5 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
Solve the quadratic equation.<br>m^2/15 -3 = 2​
Radda [10]

The answer is 5 \sqrt{3}

<h3>Explanation :</h3>

\frac{ {m}^{2} }{15}  - 3 = 2

\frac{ {m}^{2} }{15}  = 2  + 3

\frac{ {m}^{2} }{15}  = 5

{m}^{2}  = 5 \times 15

{m}^{2}  = 75

m =  \sqrt{75}

m =  \sqrt{25 \times 3}

m =  \sqrt{25}  \times  \sqrt{3}

m = 5 \sqrt{3}

CMIIW

7 0
3 years ago
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