Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

2 years ago

Destiny paid $6.60 for a dozen cupcakes for a birthday patry. What is the unit cost for each cupcake?

Digiron [165]

Answer: $.55

Step-by-step explanation:

An important thing to know is that a dozen is equal to 12.

12x= 6.60

/12 /12

x=.55

3 0

3 years ago

Read 2 more answers

Consider the probability that exactly 95 out of 153 people have not been in a car accident. Assume the probability that a given

sattari [20]

Answer:

Step-by-step explanation: it's about 1% of the population world that is of car accident

3 0

2 years ago