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Answer:
6.23% probability that the fourth part retrieved from stock is the first defective
Step-by-step explanation:
For each part, we have that:
8% probability of being defective.
100-8 = 92% probability of not being defective.
The parts are independent of each other.
What is the probability that the fourth part retrieved from stock is the first defective?
The first three work correctly, each one with a 92% probability.
The fourth is defective, with an 8% probability.
P = 0.92*0.92*0.92*0.08 = 0.0623
6.23% probability that the fourth part retrieved from stock is the first defective
Answer:
- 0.9503 ; r is not statistically significant ; 0.9031
Step-by-step explanation:
Given the following :
Age (X) :
37
41
57
65
73
Bone density (Y)
355
345
340
315
310
Using the pearson R value calculator :
The r value of the data % - 0.9503.
This value depicts a very strong negative correlation between age and density of bone.
Using the pearson R calculator to obtain the P- value, the P value obtained is .01332 and hence the r is not significant at P < 0.01.
The Coefficient of determination R^2 can be obtained by getting the square value of R
R^2 = - 0.9503^2
R^2 = 0.90307009
R^2 = 0.9031
