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Usimov [2.4K]
3 years ago
13

A bottle of laundry detergent costs $4.95 per bottle. If you have a coupon for $2.00 off and your total is $7.90, how many bottl

es of detergent did you buy? WRITE AN EQUATION AND SOLVE.
Mathematics
1 answer:
RoseWind [281]3 years ago
8 0
You bought 2 because if you add $7.90 and $2.00 the coupon you would get $9.90 so then you multiply $4.95 by 2 and you get $9.90 the exact amount we had before
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I need help with my multiplying mixed numbers by whole numbers
Lelechka [254]
So what you can do is lets say you have to multiply 5/6 by 3 you just make 3 into a mixed number 2 6/6 and multiply it like that.
6 0
3 years ago
A raft travels down river at a rate of 6 miles per hour. The total distance d in miles that the raft travels is equal to the rat
Fudgin [204]

Answer:

d=6h

Step-by-step explanation:

Speed of the raft= 6 miles per hour

Total distance (d) of the raft= rate × number of hours

d=r*h

Independent variable is the number of hours(h)

Dependent variable is the distance (d)

Equation for the situation

d=r*h

d=distance

r=rate

h=number of hours

From the question,

r=6 miles per hour

Therefore,

The equation is

d=r*h

d=6*h

d=6h

8 0
3 years ago
This is due tomorrow if someone could help me that would be great <3
kifflom [539]

<u>Hope this helped!</u>

<u>First Row</u>

\frac{5}{18}

\frac{10}{21}

\frac{9}{40}

6

5\frac{1}{3}

(this one is already done)

<u>Second Row</u>

4\frac{4}{9}

5\frac{1}{16}

\frac{13}{18}

6\frac{1}{4}

11\frac{2}{3}

5 0
3 years ago
Given the following perfect square trinomial, fill in the missing term. (2 points)<br> 9x^2 +___+25
Zielflug [23.3K]

Answer:

30x

Step-by-step explanation:

missing must be 2×3x×5=30x

9x²+30x+25=(3x+5)²

5 0
3 years ago
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
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