Can someone solve this inequality for x (x–2)a ≤ x+1 if a>1

Mathematics

1 answer:

fiasKO [112]3 years ago

7 0

Answer:

x ≤ (1+2a) / (a-1) where a > 1

Step-by-step explanation:

(x–2)a ≤ x+1

x(a) -2(a) ≤ x + 1

ax -2a ≤ x + 1 (subtract x from both sides)

ax -2a - x ≤ 1 (add 2a to both sides)

ax - x ≤ 1 + 2a (factor out x from left side)

x (a - 1) ≤ 1 + 2a

x ≤ (1+2a) / (a-1) where a > 1

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6 + 1.5x = -12 please answer

gregori [183]

Answer:

-12

Step-by-step explanation:

6 + 1.5x = -12

1.5x = -18

x = -12

3 0

2 years ago

Read 2 more answers

Here are two rectangles.

creativ13 [48]

Answer:

$\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}$

Step-by-step explanation:

Let the length of rectangle A be x units.

So, length of rectangle B

= x + 25% of x

= x + 0.25x

= 1.25x

Let the width of rectangle A be y units

So, Width of rectangle B

$= \frac{3}{5}\times x\\=0.6x$

Area of rectangle A = xy

Area of rectangle B

= 1.25x * 0.6y

= 0.75xy

$\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{xy}{0.75xy}\\\\\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{1}{0.75}\\\\\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{100}{75}\\\\\red{\bold{\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}}} \\\\$