Can someone solve this inequality for x
(x–2)a ≤ x+1 if a>1
1 answer:
Answer:
x ≤ (1+2a) / (a-1) where a > 1
Step-by-step explanation:
(x–2)a ≤ x+1
x(a) -2(a) ≤ x + 1
ax -2a ≤ x + 1 (subtract x from both sides)
ax -2a - x ≤ 1 (add 2a to both sides)
ax - x ≤ 1 + 2a (factor out x from left side)
x (a - 1) ≤ 1 + 2a
x ≤ (1+2a) / (a-1) where a > 1
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