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expeople1 [14]
3 years ago
13

7. The bottom of a river makes a V-shape that can be modeled with the absolute value function,

Mathematics
1 answer:
hjlf3 years ago
8 0

Answer:

If one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480

Step-by-step explanation:

Given that:

The absolute value function:

d(h) = \dfrac{1}{6}|h - 300| - 50

To calculate the position of the buoy where the river bottom is 20 feet below the surface, we equate the absolute value function to the negative value of 20 feet and then solve it for h.

d(h) = -20

d(h) = \dfrac{1}{6}|h - 300| - 50 = -20

Let us add the sum of 50 on both sides, then:

= \dfrac{1}{6}|h - 300| - 50+50 = -20+50

= \dfrac{1}{6}|h - 300| = 30

By multiplying 6 on both sides, we have:

|h - 300| = 30 (6)

|h - 300| = 180

We can attempt the above expression by rewriting it as two equations:

h - 300 = 180   or     h  - 300  = - 180

Let us add 300 to both sides from the two expressions above:

h - 300 + 300 = 180 + 300     or   h - 300 + 300   = -180  + 300

h = 480     or  h = 120

Thus, if one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480

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3 years ago
Let L be a tangent line to the hyperbola x y = 2 at x = 9 . Find the area of the triangle bounded by L and the coordinate axes.
mafiozo [28]

Answer:

A = 4

Step-by-step explanation:

The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:

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The numerical value of the slope is:

y' = -2 \cdot (9)^{-2}\\y' = -\frac{2}{81}

The component of the y-axis is:

y = \frac{2}{9}

Now, the tangent line has the following mathematical model:

y = m \cdot x + b

The value of the intercept is found by isolating it within the equation and replacing all known variables:

b = y - m \cdot x

b = \frac{2}{9}-(-\frac{2}{81} )\cdot (9)\\b = \frac{4}{9}

Thus, the tangent line is:

y = -\frac{2}{81}\cdot x + \frac{4}{9}

The vertical distance between a point of the tangent line and the origin is given by the intercept.

d_{y} = \frac{4}{9}

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:

-\frac{2}{81}\cdot x + \frac{4}{9}=0

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The area of the triangle is computed by this formula:

A = \frac{1}{2}\cdot d_{x}\cdot d_{y}

A = \frac{1}{2}\cdot (18)\cdot (\frac{4}{9} )

A = 4

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Answer:

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