D , because 28-9=21 and 21=x
Answer:
(a) f'(1)=-4
(b) y+4x-4=0
Step-by-step explanation:
<u>Tangent Line of a Function</u>
Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.
We are given

The derivative is

(a) The slope of the tangent line at (1,0) is


(b) The equation of the tangent line can be found with the general formula of the line:

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

Or, equivalently

Answer:The line goes through the points (4,-3) and (0,-2), so its gradient is (-2-(-3))/(0-4) = -1/4. The y-intercept is -2 because f(0)=-2. So the equation of the line is y = -1/4 x - 2.This can be represented by the linear function f(x) = (-1/4)x - 2. The composite function ff is given by ff(x) = f(-1/4 x - 2) = (-1/4)((-1/4)x - 2) - 2 = x/16 - 3/2.HOPE'S THIS HELP'S
Answer:
A,B, AND C
Step-by-step explanation: