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2 years ago

How do I solve this?

Mathematics

1 answer:

sp2606 [1]2 years ago

8 0

I dont know sprry but h can look it up

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A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

2 years ago

Simplify the expression: –5(6 − 2y) =

Vadim26 [7]

-30+10y
hope this helps!

3 0

2 years ago

Read 2 more answers

Evaluate the logarithmic expression log6 1

AlekseyPX

Answer:

Logarithm base 6 of 1 is 0.

3 0

3 years ago

Age If you add Natalie's age and Fred's age, the result is 40. If you add Fred's age to 4 times

jolli1 [7]

Answer:

Fred is 28 yrs old. Nathalie is 12yrs old

Step-by-step explanation:

Let Nathalie's age be x

Let Fred's age be a

x+a=40 yrs•••••1

4x+a=76yrs•••••2

a=40-x

Substitute a for 40-x in equation (2)

4x+40-x=76

3x=76-40

3x=36

x=12

a=40-12

a=28

5 0

2 years ago

How do I solve this absolute value in quality problem |2t + 2/3|≤4

xenn [34]

Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

2t + 2/3≤4

(2t + 2/3≤4)*3

6t+2≤12

6t≤10

t≤10/6

t≤5/3

2t + 2/3>=-4

(2t + 2/3>=-4)*3

6t + 2>=-12

6t>=-14

t>=-14/6

t>=-7/3

-7/3≤t≤5/3

6 0

1 year ago

How do I solve this?​

How do I solve this?