Answer:
I have a formula for differentiating a questions on differentiation
Step-by-step explanation:
I have not published it yet but can give a brief summary of it will later use it to solve questions here after publishing it
any time you a given a function or a question to differentiate always write it in this form y=am...will explain the rest later after publishing it. it works for all kind of differentiation questions like product or quotient type of questions
120:100 or 6:5 so 24:x
if ratios are the same then the reciprocal of one of the ratios times the other ratio should equal 1 so 6/5 times x/24=1
6x/120, x=20
20/8=x/6
x=15
they are similar so the proportion is the same
Answer:
364/27
Step-by-step explanation:
9, 3, 1, ... is a geometric sequence with common ratio r = 1/3.
The nth term is a1rn-1.
If a1rn-1 = 1/27, then 9(1/3)n-1 = 1/27
32(3-1)n-1 = 3-3
3231-n = 3-3
33-n = 3-3
3-n = -3
n = 6
The sum, Sn, of the first n terms of a geometric sequence is given by Sn = a1(1 - rn) / (1 - r).
So, 9 + 3 + 1 + ... + 1/27 = S6 = 9(1 - (1/3)6) / (1 - 1/3)
= 9(1 - 1/729) / (2/3)
= (27/2)(728/729) = 364/27
