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amid [387]
3 years ago
14

How do you write a recursive formula

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0
You need to show how a term of formula is based on a previous term.

For example, let's say you have the sequence 3, 6, 9, 12, ...
(multiples of 3).

As a regular function, you can have y = 3x, for the domain of all integers greater than 0. Since the domain is 1, 2, 3, 4, ..., when you multiply those numbers by 3, to get y, you generate the sequence.

To define the sequence recursively, you must base each new number on the previous number.

Start by stating the first term.

a1 = 3

If you look at the sequence, 3, 6, 9, ..., you see it has a constant difference, and it is an arithmetic sequence, so to generate a term, you need to add 3 to the previous term.

Once we defined the first term to be 3, the next term is a2 = 3 + 3 = 6
Then a3 = 6 + 3 = 9, etc.

To define the sequence recursively, just generalize the addition of 3 to a term to get the next term.

a_{1} = 3

 a_{n} = 3 a_{n - 1}
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Which of the following expressions is equivalent to the radical expression?
qwelly [4]
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The denominator of the exponent is the root we are taking.  The numerator is the exponent of the radicand.  This means 3 will be the denominator, since it is a cubed root, and 2 will be the numerator of m while 5 will be the numerator of n.
4 0
3 years ago
Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
professor190 [17]
Ok, here we go.  Pay attention.  The formula for the arc length is AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx.  That means that to use that formula we have to find the derivative of the function and square it.  Our function is y = 4x-5, so y'=4.  Our formula now, filled in accordingly, is AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx (that 1 is supposed to be negative; not sure if it is til I post the final answer).  After the simplification we have the integral from -1 to 2 of \sqrt{17}.  Integrating that we have AL= \sqrt{17}x from -1 to 2.  2 \sqrt{17}-(-1 \sqrt{17} ) gives us 3 \sqrt{17}.  Now we need to do the distance formula with this.  But we need 2 coordinates for that.  Our bounds are x=-1 and x=2.  We will fill those x values in to the function and solve for y.  When x = -1, y=4(-1)-5 and y = -9.  So the point is (-1, -9).  Doing the same with x = 2, y=4(2)-5 and y = 3.  So the point is (2, 3).  Use those in the distance formula accordingly: d= \sqrt{(2-(-1))^2+(3-(-9))^2} which simplifies to d= \sqrt{9+144}= \sqrt{153}.  The square root of 153 can be simplified into the square root of 9*17.  Pulling out the perfect square of 9 as a 3 leaves us with 3 \sqrt{17}.  And there you go!
5 0
3 years ago
You decide to put the Gamer table on sale for 20% off. You normally charge $210 for this table. What is the amount of the discou
kvasek [131]
First, you would multiply $210 by 20%
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Then to find the sale price, you would subtract that 42 that you just got from 210,

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5 0
3 years ago
Simplify. 10 + 51 -10 + 51 41
tatuchka [14]

Answer:

52.12

Step-by-step explanation

PEMDAS

Adding comes before subtracting

10+51=61

10+51 41=51.51

61-51.51=-52.12

3 0
3 years ago
V=r^2+R^2h; Solve for R
Ne4ueva [31]
Solve for R by simplifying both sides of the equation, the isolating the variable. 
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