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RUDIKE [14]
3 years ago
9

Can someone please help me these are the questions. : Evaluate each numerical expression. Apply

Mathematics
1 answer:
Lorico [155]3 years ago
6 0
I don’t know that one sorry
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plzzz help A model train is on a track 100 cm from its starting point. Turning a switch displaces the train either forward or ba
Ad libitum [116K]

Answer: B.  |x-100| = 25

Explanation:

Draw out a number line. Mark 75, 100 and 125 on the number line as points A, B, and C in that order. Don't worry about the spacing.

The value of x represents where the train is. So if we had say x = 85, then it would be at location 85 on the number line. Writing |x-100| is the distance from x to 100. The absolute value ensures the distance is never negative. We want this distance to be 25 because after traveling 25 cm, the switch is turned, and the train goes the other way.

6 0
4 years ago
A pair of shorts are £15 in a 40%. What was the non-sale price
lana66690 [7]

Answer:

£10.71

Step-by-step explanation:

Given the original price including discount od shorts = £15

Percent discount = 40%

Original price = x

Using the expression to calculate x

x + (40%of x) = 15

x +0.4x = 15

1.4x = 15

x = 15/1.4

x = £10.71

Hence the non sale price is £10.71

4 0
3 years ago
G.O has 3 orange picks for every 2 green. If there are 25 picks in all, how many picks are orange?
Tomtit [17]

There will be 15 orange pickles and 10 green picks

3 0
3 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
3 years ago
What is the y-intercept of this line?
GaryK [48]

12, 8, 4, 0

Step-by-step explanation:

Thank Me. Super.

4 0
3 years ago
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