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adell [148]
2 years ago
10

How do I solve 2x^2-32=0 using the square root method?

Mathematics
2 answers:
Ainat [17]2 years ago
3 0

Answer:

x = -4,4

Step-by-step explanation:

2x^2 - 32 = 0

2x^2 = 32

x^2 = 16

x = either -4, 4

If there is only space for one answer put 4.

Hope this helped!

raketka [301]2 years ago
3 0

Answer: 4 or -4

Step-by-step explanation:

2x^2-32+32=0+32

2x^2=32

1/2*2x^2=32*1/2

x^2=16

x=4 or -4

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3 years ago
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Answer:

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3 years ago
Still need help on this please need help
Goryan [66]
The discriminant is the value of b²-4ac
in this case, b=-8, a=4, c=4, so the discriminant is (-8)²-4*4*4=0
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3 years ago
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erica [24]
The 3rd one I believe
5 0
3 years ago
PLEASE HELP QUICK AND EXPLAIN. I'M OFFERING 25PTS (It's only worth 10pts) AND BRAINLIEST ANSWER. I'VE POSTED LIKE 5 TIMES PLEASE
Vladimir79 [104]

Answer:

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A) Graph the points (length is x, weight is y)

B) Find slope and substitute 75 for x value

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Step-by-step explanation:

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