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adell [148]
2 years ago
10

How do I solve 2x^2-32=0 using the square root method?

Mathematics
2 answers:
Ainat [17]2 years ago
3 0

Answer:

x = -4,4

Step-by-step explanation:

2x^2 - 32 = 0

2x^2 = 32

x^2 = 16

x = either -4, 4

If there is only space for one answer put 4.

Hope this helped!

raketka [301]2 years ago
3 0

Answer: 4 or -4

Step-by-step explanation:

2x^2-32+32=0+32

2x^2=32

1/2*2x^2=32*1/2

x^2=16

x=4 or -4

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What is the value of x?​
pashok25 [27]

Answer:x = 121 degrees

Step-by-step explanation:

X is 121 degrees because it is a same side interior angle to the 59 degree angle. 180-59 = 121.

3 0
3 years ago
Estimate 102.3 divided by 4.7
qwelly [4]

Answer:

20

Explanation:

To estimate, we round.  102.3 rounds to 100 and 4.7 rounds to 5; this means we divide 100/5, which is 20.

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3 years ago
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7. Which of the following is an example of a proper fraction?
Ymorist [56]

Answer:

C.4/17

Step-by-step explanation:

A proper fraction has a numerator that is less than the denominator

A. 11/10  11>10  improper

B. 15/2  15>2  improper

C.4/17  4 < 17 proper

D.6/6  6=6  improper

7 0
3 years ago
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Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
How do i do this, I'm really really really really really really really really really really really really really really really c
loris [4]
I told this to someone else also...

The best thing ever is Photomath! Go to the app store on your phone, tablet, etc. and download Photomath. It literally does all your math for you and even shows the steps!! I use it all the time. :)
8 0
3 years ago
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