3 years ago

How do I solve 2x^2-32=0 using the square root method?

Mathematics

2 answers:

Ainat [17]3 years ago

3 0

Answer:

x = -4,4

Step-by-step explanation:

2x^2 - 32 = 0

2x^2 = 32

x^2 = 16

x = either -4, 4

If there is only space for one answer put 4.

Hope this helped!

raketka [301]3 years ago

3 0

Answer: 4 or -4

Step-by-step explanation:

2x^2-32+32=0+32

2x^2=32

1/2*2x^2=32*1/2

x^2=16

x=4 or -4

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