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2 years ago

Which scatterplot represents the data given in the table which shows the number of oranges in bags and the weights of the bags?

Mathematics

2 answers:

Elan Coil [88]2 years ago

5 0

Answer:

i think its A

Step-by-step explanation:

lisov135 [29]2 years ago

4 0

Answer:

I would need to see an actual table to answer this question.

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Find the value of y if M is the midpoint of LN. 9y - 4 6y + 5 N help plz

AURORKA [14]

Answer:

If M is the midpoint, then LM = MN

3x - 2= 2x +1

x = 3

So LM = 3x - 2 = 9 -2 = 7

LM = 7

8 0

3 years ago

How to find x in a quadrilateral

evablogger [386]

X = 360 - (122+58+58)
x = 360 - 238
x = 122

6 0

2 years ago

A triangle has vertices at L(2, 2), M(4,4), and N(1,6). The

pav-90 [236]

Answer:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6)

Step-by-step explanation:

90 degree rotation from (x,y) results in (-x, y) and 180 degree results in (-x,-y)

The coordinates will change accordingly

L(2,2) will become L'(-2,-2)

M(4,4) will become M'(-4,-4)

and

N(1,6) will become N'(-1,-6)

So the correct statements are:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6) ..

8 0

3 years ago

Read 2 more answers

ALGUIEN QUE ME AYUDE A COMPLETAR LOS CUADRADOS

g100num [7]

The answer is fjfjfj

8 0

2 years ago

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago