Answer:
I'm not 100 percent sure but but part a is
0 0
6 18
12 36
and then part b is letter A
Step-by-step explanation:
hope this helps
Answer:
m=-7/2
Step-by-step explanation:
(5 • (m + 2) - m) - (2m + 3) = 0
2m + 7 = 0
3.1 Solve : 2m+7 = 0
Subtract 7 from both sides of the equation :
2m = -7
Divide both sides of the equation by 2:
m = -7/2 = -3.500
We are given y = kxz
We also know 32 = k×6×8, so k = 32/48 = 2/3.
We are then asked to solve:
Answer:
IQR: 20
Range: 52
Step-by-step explanation:
IQR = 88 - 68 = 20
Range = 100 - 48 = 52
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall that
tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)
so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:
(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall the double angle identity for cosine,
cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1
so the 1 in the denominator also vanishes:
(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))
Recall the Pythagorean identity,
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1
which means
sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):
-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))
Cancel the cos²(<em>θ</em>) terms to end up with
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2
