$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{9}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-7}{4-(-2)}\implies \cfrac{9-7}{4+2}\implies \cfrac{2}{6}\implies \cfrac{1}{3}$

7 0

3 years ago

Read 2 more answers

Which of the following is an identity? Also, please include an explanation.

Lerok [7]

$cot\theta= \frac{ cos \theta}{ sin \theta } \\ sec\theta = \frac{1}{ cos \theta } \\ \\ \\ sin \theta cot\theta sec\theta \\ = sin \theta \cdot \frac{ cos \theta}{ sin \theta } \cdot \frac{1}{ cos \theta } \\ = \frac{ sin \theta}{ sin \theta } =1 \\$

sinθcotθsecθ = 1

6 0

3 years ago

Calculate the side lengths a and b to two decimal places.

Strike441 [17]

Answer:

A.)=24.78

B.)=26

C.)=7.33

D.)=25.44

Step-by-step explanation:

A.)11.40+13.38=24.78

B.)11+15=26

C.)4.18+3.15=7.33

D.)10.92+14.52=25.44

7 0

2 years ago

Read 2 more answers

Mr. Walker is looking at the fundraiser totals for the last five years.

klemol [59]

Answer:

the median is $1.60 greater than the mean

7 0

2 years ago