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2 years ago

5

PLEASE HELP MEEE I'm failing and I need to pass:(

1 answer:

Dahasolnce [82]2 years ago

3 0

Answer:

girl/boy use photomath if ur failing or just use these.

Step-by-step explanation:

11. 5x^2-6x-12

12. 2x(4y+5x)

13.3y^2+16xy

if you need the rest use photomath I am sure it will come to the same answers I got.

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y+4=-2(x-4)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=-2(x-4)

y+4=-2(x-4)

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2 years ago

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Step-by-step explanation:

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Find the zeros of the function g(x) = x2 - 6x - 16 by factoring. what is the largest zero of the function? enter a number only.

aleksandrvk [35]

(X-8)(x+2) is the factored equation. Ur zeros r -2 and 8. So the largest should be 8?

5 0

2 years ago

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.

$\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}$

$⇢ 7 + 9 + 11 = 27$

$⇢ 27 = 27$

⇢ L. H. S. = R. H. S.

$\sf\blue{Hence\:verified.}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

4 0

2 years ago

Which expression is equivalent to 4/9(2n - 3)

krek1111 [17]

Answer:

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Step-by-step explanation:

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