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alexandr402 [8]
3 years ago
8

HELP ASAP!!!!!

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

14 mph

Step-by-step explanation:

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Help! how do i answer this
navik [9.2K]
Idk but ima try to figure it out ok
7 0
2 years ago
which is a correct definition for a right angle? a.an angle with a measure that equals the measure of a square corner b.an angle
Sunny_sXe [5.5K]
A. an angle with a measure that equals the measure of a square corner
6 0
3 years ago
2(1 − x) = 9(1 + 2x) + 52(1 − x) = 9(1 + 2x) + 5
marusya05 [52]

Solving the equation 2(1-x) = 9(1 + 2x) + 5 we get x=-\frac{3}{5}

Step-by-step explanation:

We need to solve the equation 2(1-x) = 9(1 + 2x) + 5 and find value of x

Solving:

2(1-x) = 9(1 + 2x) + 5\\2-2x=9+18x+5\\Adding\,\,-18x\,\,on\,\,both\,\,sides:\\2-2x-18x=9+5\\Adding\,\,-2\,\,on\,\,both\,\,sides\\-20x=14-2\\-20x=12\\x=\frac{12}{-20}\\x=-\frac{3}{5}

So, solving the equation 2(1-x) = 9(1 + 2x) + 5 we get x=-\frac{3}{5}

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

7 0
3 years ago
What is the width of a rectangle with an area of 5/8 in. squared and a length of 10 inches?
Ad libitum [116K]
5/8=10×w this is my equation then i divide by 10 on both sides
w=6.25
6 0
3 years ago
Can atriangle be formed with side lengths of 5cm. 10cm and 15cm
andreyandreev [35.5K]
Theorem of cosine:
a²=b²+c²-2bc(cos α)  ⇒cos α=-(a²-b²-c²) / 2bc

In this case:
a=15 cm
b=10 cm
c=5 cm

cos α=-(15²-10²-5²) / 2*10*5
cos α=-100 / 100
cos α=-1

A=arc cos -1=180º  This is impossible, because:

A+B+C=180º; then  B=C=0º  This is impossible for make a triangle  (B>0 and C>0 if we want to make a triangle).  

Therefore: it is not possible can make a triangle with side lengths of 5 cm, 10 cm and 15 cm.

3 0
3 years ago
Read 2 more answers
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