For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>
Answer:
- x > -2
- n ≤ -2 or n ≥ 8
Step-by-step explanation:
<h3>1.</h3>
Add 7x-2 to both sides and collect terms.
2x +2 -6x +7x -2 > -4 -7x +7x -2
3x > -6
x > -2 . . . . . . . divide by 3
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<h3>2.</h3>
Solve these one at a time, and form the union of the answers.
1 +7n ≤ 15 . . . .given
7n ≤ 14 . . . . . . subtract 1
n ≤ 2 . . . . . . . divide by 7
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-2n -2 ≤ -18 . . . given
-2n ≤ -16 . . . . . add 2
n ≥ 8 . . . . . . . . divide by -2
The solution is n ≤ -2 or n ≥ 8.
Answer:5 1/3 times
Step-by-step explanation:
Answer:
She should ask the people she pulled out first then pull out more and ask them
Step-by-step explanation:
First find 28% of $19.50:
($19.50) / (100) × (28) = $5.46
Now minus the 285 from the original price:
($19.50) - ($5.46) = $14.04
The answer is $14.04
Hope it helped :)
