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anzhelika [568]
3 years ago
13

Using Point Slope Formula, write an equation that passes through (-2, 6) and ( 8, 9)

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

y - 9 = 3/10(x - 8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-2, 6)

Point (8, 9)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute [SF]:                    \displaystyle m=\frac{9-6}{8+2}
  2. Subtract/Add:                      \displaystyle m=\frac{3}{10}

<u>Step 3: Write Function</u>

<em>Plug in variables into general form.</em>

y - 9 = 3/10(x - 8)

y - 6 = 3/10(x + 2)

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Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

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Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

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