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uranmaximum [27]
3 years ago
12

What is the average rate of change of the line whose equation is:

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

Rate of change = -12

Step-by-step explanation:

y − 3 = −12(x + 4)

Expanding, we have;

y - 3 = -12x - 48

y = -12x - 48 + 3

y = -12x - 45

Now, formula for rate of change is;

Rate of change = (y(x + h) - y)/h

y(x + h) is; y = -12(x + h) - 45

This gives;

Rate of change = (-12(x + h) - 45 + 12x + 45)/h

Rate of change = (-12x - 12h - 45 + 12x + 45)/h

Rate of change = -12h/h

Rate of change = -12

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Y  = 50 - 7.5X   if 35 m² Area left to paint after 2 hrs out of total 50m²

Step-by-step explanation:

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3 years ago
Is there
Basile [38]

Answer:

no

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no because 29 is a prime number, meaning its only factors are 1 and 29. if you were to have more than 1 book on each shelf then you would go into half and quarters of books.

8 0
2 years ago
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Lisa has 3 quarts of milk. Sanjay has 12 pints of milk. Who has more?
Ira Lisetskai [31]

Sanjay, because quarts are twice as big as pints.

Step-by-step explanation:

Given

Milk quantity for Lisa = 3 quarts

Milk quantity for Sanjay = 12 pints

We have to convert both quantities in same unit so that we can compare both quantities.

We know that there are two pints in a quart.

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Lisa will have:

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Hence,

Sanjay, because quarts are twice as big as pints.

Keywords: Units, measurement

Learn more about units at:

  • brainly.com/question/8280736
  • brainly.com/question/8224301

#learnwithBrainly

4 0
2 years ago
What is the value of s in the equation 4(2s − 1) = 7s + 12? (4 points)
notka56 [123]

Answer:

B) 16

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s-4=12

s=16

3 0
3 years ago
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a buret is a tool designed to transfer precise amounts of liquid .A buret initially contains 70.00 millimeters of a solution and
katrin [286]

Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

a = volume of each drip

\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}

after how many drips will the volume of the solution in the buret and beaker be equal ?​ Vbu = Vbk:

\begin{gathered} Vbu=Vbk \\ 70-0.05x=20+0.05x \\ \text{Solve for x:} \\ 0.1x=70-20 \\ 0.1x=50 \\ x=\frac{50}{0.1} \\ x=500 \end{gathered}

5 0
1 year ago
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