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uranmaximum [27]
3 years ago
12

What is the average rate of change of the line whose equation is:

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

Rate of change = -12

Step-by-step explanation:

y − 3 = −12(x + 4)

Expanding, we have;

y - 3 = -12x - 48

y = -12x - 48 + 3

y = -12x - 45

Now, formula for rate of change is;

Rate of change = (y(x + h) - y)/h

y(x + h) is; y = -12(x + h) - 45

This gives;

Rate of change = (-12(x + h) - 45 + 12x + 45)/h

Rate of change = (-12x - 12h - 45 + 12x + 45)/h

Rate of change = -12h/h

Rate of change = -12

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<h3><u><em>Solution:</em></u></h3>

Given that,

The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing back and forth

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T=2\pi \sqrt{\frac{L}{32} }\\\\ \sqrt{\frac{L}{32} }=\frac{T}{2 \pi}\\\\\text{Taking square root on both sides }\\\\\frac{L}{32} = \frac{T^2}{4 \pi^2}\\\\L = \frac{T^2}{4 \pi^2} \times 32\\\\L = \frac{T^2}{\pi^2 } \times 8

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L = \frac{1.75^2}{3.14 \times 3.14} \times 8\\\\L = \frac{3.0625}{9.8596} \times 8\\\\L = 2.485

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