The true statements about Marcus graph are:
- The initial cost of phone service 1 is greater than the initial cost of phone service 2
- The unit rate of phone service 2 is greater than the unit rate of phone service 2
<h3>How to determine the true statement</h3>
From the complete question, we have the following parameters:
<u>Phone service 1</u>
- Initial cost: $40
- Rate: $8.50 per service
<u>Phone service 2</u>
- Initial cost: $30
- Rate: $10.50 per service
By comparing the above parameters:
- The initial cost of phone service 1 is greater than the initial cost of phone service 2
- The unit rate of phone service 2 is greater than the unit rate of phone service 2
The above statements represent the true statements about the Marcus' graph
Read more about graphs at:
brainly.com/question/14323743
Answer:
3.6477seconds
Step-by-step explanation:
Sarah the cheetah ran the 100 meters in 5.9523s. Subtract 5.9523 from 9.6
Answer:

Step-by-step explanation:
Set builder notation-
It is a notation for representing a set by enumerating its elements and stating the properties that its members must satisfy.
The given set is,

This set is comprised of all negative integers. So symbol Z should be used in this case.
The set builder notation for this set is,

A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
-3(2x-3)<3
(-3(2x-3))(-1)<3(-1)
3(2x-3)>-3
(3(2x-3))/3>-3/3
2x-3>-1
2x-3+3>-1+3
2x>2
2x/2>2/2
x>1