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Leona [35]
3 years ago
7

A train travels at 100 miles per hour. An equation can be written that compares the time (t) with the distance (d). Define the d

omain and range.
a. the domain is time (t) and the range is distance (d).
b. the domain is time (t) and the range is 100.
c. the domain is 100 and the range is time (t).
d. the domain is distance (d) and the range is time (t)
Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

The answer would be, A the domain is time and the range is distance.

Step-by-step explanation:

The train is travelling at 100 miles per hour, thus the equation would be d=100t meaning that the distance equals 100 times the amount of time. Now, that means that the input is the amount of time it's been going, and the input is the domain. if the input is the domain,  then the only thing left to be the input (range) is the y value, or, in this case, the d value.

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What is the value of x in the equation -2/3 x + 9 = 4/3 x - 3?​
anygoal [31]

Answer:

x = 6

Step-by-step explanation:

We want to solve:

\frac{-2}{3} x+9=\frac{4}{3} x-3

First, isolate the variable by moving all the terms with x to one side and all the constants to the other side:

\frac{4}{3}x +\frac{2}{3} x=9+3

Combining the fraction on the left, we get:

\frac{6}{3} x=12

6/3 = 2, so:

2x = 12

Dividing both sides by 2 yields:

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Step-by-step explanation:

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7 0
2 years ago
30=7r+5 what’s does r stand for
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
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