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murzikaleks [220]
3 years ago
13

A textbook store sold a combined total of 414 physics an chemistry textbooks in a week. The number of physics textbooks sold was

60 more than the number of chemistry textbooks sold. How many textbooks of each type were sold?
Mathematics
1 answer:
Nikolay [14]3 years ago
8 0

Answer:

chemistry textbooks:177

physics textbooks:237

Step-by-step explanation:

414-60=354

354/2=177

177+60=237

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A rectangular aquarium 3 ft. x 2 ft. 1 ft. is 2/3 full of water. In cubic feet, how much water is in the tank
tatuchka [14]

To find the volume of a rectangular prism, we must multiply the length * width * height.


In this case,


Volume = 3 ft * 2 ft * 1 ft

= 6 ft^3


Because this tank is 2/3 full with water, to find out how much water is in the tank, we must multiply 2/3 by the total volume of the tank (6 ft^3).


2/3 * 6 ft^3 = 4 ft^3


This means that there are 4 cubic feet of water in the tank.


Hope this helps!

6 0
3 years ago
The measure of c is .
mina [271]

Answer:

c^2=a^2+b^2

c^2=6^2+8^2

c^2=36+64

c=10

but still do not understand why peoples are asking that basic

4 0
3 years ago
Read 2 more answers
In October 1945, the Gallup organization asked 1,487 randomly sampled Americans, "Do you think we can develop a way to protect o
GalinKa [24]

Answer:

Yes. There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>In October 1945, the Gallup organization asked 1487 randomly sampled Americans, "Do you think we can develop a way to protect ourselves from atomic bombs in case other countries tried to use them against us?"</em><em> with 788 responding yes.</em><em> Did a majority of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945? Use the α=0.05 level of significance.</em>

This is a hypothesis test for a proportion.

The claim is that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Then, the null and alternative hypothesis are:

H_0: \pi=0.5\\\\H_a:\pi>0.5

The significance level is 0.05.

The sample has a size n=1487.

The sample proportion is p=0.53.

p=X/n=788/1487=0.53

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{1487}}\\\\\\ \sigma_p=\sqrt{0.000168}=0.013

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.5-0.5/1487}{0.013}=\dfrac{0.03}{0.013}=2.288

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>2.288)=0.011

As the P-value (0.011) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

8 0
3 years ago
GIVING 20 POINTS I NEED IT ASAP
Elza [17]

Answer:

AC= 5x - 3

Step-by-step explanation:

Segments Addition:

AB + BC = AC

(2x+12) + 3x-15 = AC

5x - 3 =AC

4 0
3 years ago
Help please and thank you
MAXImum [283]
Answer: 18 12x150%=18 hope this helped
7 0
3 years ago
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