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ddd [48]
3 years ago
6

Tyler has run 15 miles this month for the rest of the month he plans to run the same number of miles each day there are 12 days

left in the month before the end of the month tyler needs to run at least 35 miles to meet his goal
(a) 12m - 15 > 35

(b) 12m - 15 15 +12m

(c) 35 >15 +12m

(d) 35 < 15 +12m
Mathematics
1 answer:
prohojiy [21]3 years ago
7 0

Answer:

(d) 35<15+12m is the answer

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(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

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(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

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(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

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<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

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If ABC type question, then sometimes. If its extended, then only when the lines coincide with each other or if one of the lines aren't linear.

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Let's solve  your equation step-by-step

16.8-(-23.72)-31.3=x

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16.8-(-23.72)-31.3=x

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9.22=x

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Step 2: flip the equation

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