Answer:
area of the sector = 360π cm²
Step-by-step explanation:
To calculate the area of the sector, we will follow the steps below;
First write down the formula for calculating the area of a sector.
If angle Ф is measured in degree, then
area of sector = Ф/360 × πr²
but if angle Ф is measured in radians, then
area of sector = 1/2 × r² × Ф
In this case the angle is measured in radiance, hence we will use the second formula
From the question given, radius = 15 cm and angle Ф = 8π/5
area of sector = 1/2 × r² × Ф
=1/2 × 15² × 8π/5
=1/2 ×225 × 8π/5
=360π cm²
area of the sector = 360π cm²
Answer:
In this case, we have a linear equation:
y = 3*x - 2
And we want to graph this in the interval –3 ≤ x ≤ 3
Because this is a linear equation, to graph it we can just evaluate the equation in both extremes of the interval to find the two extremes of the graph.
Then we just need to connect these points with a segment, and that will be the graph of our equation.
Because the symbols used are: ≤
We need to graph the extremes with a black dot, which means that the point is included in the graph (would be different if we had -3 < x < 3)
The first extreme is when we have x = -3
y = 3*(-3) - 2 = -9 - 2 = -11
Then we have one extreme at (-3, -11)
The other is when x = 3
y = 3*3 - 2 = 9 - 2 = 7
Then the other extreme is at (3, 7)
Now we just need to draw these two points and connect them, an example of this can be seen in the image below:
76 + 4 is 80... don't know what you're asking
Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is

The standard deviation of the random sample is







Therefore, The mean is 2.5 and the standard deviation is 1.08.