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Ksenya-84 [330]
2 years ago
11

!!!!!!!!!! !!!!!!!!!!!!

Mathematics
1 answer:
jeyben [28]2 years ago
4 0

Answer:

B

Step-by-step explanation:

6.5 * 24 = 156

Therefore B

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Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
A 29<br> B 58<br> C 13.5<br> D 14.5
matrenka [14]
The answer is d actually I don’t know
8 0
2 years ago
Simplify! (a^3b)(abc)<br><br> A) a^2bc^5<br> B) a^4b^2<br> C) a^4b^2c<br> D) a^4bc
fenix001 [56]

Answer:

a^{3}*b*(abc)=a^{4} * b^{2} * c

Step-by-step explanation:

you use the distributive property

7 0
3 years ago
Read 2 more answers
Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to th
KIM [24]
228 - 48 = 180

180/48 = 3.75

Its increase 375%
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3 years ago
Solve for x.<br> 79<br> (8x - 4)<br> 3<br> -(3x + 17)
Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

maybe... i am 99.99% sure

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