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3 years ago

Solve the two step equation 8x+38=60

Mathematics

1 answer:

Paladinen [302]3 years ago

8 0

Answer:

x = 2.75

Step-by-step explanation:

The goal here is to isolate the variable, or to get x by itself. We can do this by using simple math. The first step is to move every thing to the opposite side of x. We do this by subtracting 38 from 60, which leaves us with 22. Now we want divide 22 by 8. After doing this we are left with the equation x = 2.75. I know that at first fractions and decimals seem annoying and they feel like a lot of work. But if you take a second to really look at them, you will realize they are not that bad. As in most cases with math, looks can be deceiving

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Supposr you're making a soup that uses 5 cups of chicken broth and 3/4 teaspoons of corn starch for 8 servings. You need to make

Svet_ta [14]

Answer:

The answer is C, 7.5 cups

Step-by-step explanation:

You can calculate the relationship between 8 and 12 (12/8) which is simplified as 3/2 and then multiply 3/2 by 5.

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2 years ago

What is the value of 6 + 2x2, when x = 3? X

Lyrx [107]

6 + 2(x)2
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2 years ago

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There are 910 scooters in a show room out of which 654are new and rest are old. find out number of old scooters

Soloha48 [4]

Answer:

254

Step-by-step explanation:

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1 year ago

Can somebody help me find the area of the shape asap

Natasha_Volkova [10]

Answer:

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hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago