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lukranit [14]
3 years ago
11

A bag contains 5 white marbles and 30 blue marbles. If a representative sample contains 2 white ​marbles, then how many blue mar

bles would you expect it to​ contain? Explain. Because the ratio of white marbles to blue marbles is ▼ 6:5 6:1 5:6 1:6 in the​ population, the expected number of blue marbles is nothing times the number of white marbles in the representative sample. There should be nothing blue marbles.
Mathematics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

6:1

Step-by-step explanation:

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Jesse looks out the attic window of his home, which is 22 ft above the ground. At an angle of elevation of 35° he sees a bird si
Ket [755]

Answer:

Step-by-step explanation:

6 0
3 years ago
Solve by substitution<br> -4x+y=6<br> -5x-y=21
inn [45]

Answer:

x=-3, y=-6. (-3, -6).

Step-by-step explanation:

-4x+y=6

-5x-y=21

--------------

-9x=27

x=27/-9

x=-3

-5(-3)-y=21

15-y=21

y=15-21

y=-6

7 0
3 years ago
Of 24 employees at a local supermarket, 13 work as cashiers and 11 stock shelves. If 4 employees are selected at random to work
kenny6666 [7]

Answer:

The required probability is, \simeq 0.06729

Step-by-step explanation:

Of 24 employees at a local supermarket, 13 work as cashiers  and 11 stock shelves. If 4 employees are selected at random to work overtime, then

P( all 4 are cashiers) = \frac{^{13}{C}_{4}}{^{24}{C}_{4}}

                                 \simeq 0.06729

4 0
3 years ago
Read 2 more answers
dion flips a coin 20 times and records if it comes up heads. if getting heads is a success, what is the probability of a success
kolbaska11 [484]

Answer:

\frac{1}{2}

Step-by-step explanation:

The probability of success (getting heads) on one roll DOESNT affect other rolls, so we need to find probability of getting a head in a roll.

Probability is defined as the number of favorable outcomes divided by the total number of outcomes.

<em>Here, favorable outcome is getting a head. So, on one roll, getting a head is 1. Also, the total number of outcomes is either a head or a tail. So total number of outcomes is 2.</em>

Thus,

P(Heads) = 1/2

3 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
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