Let x be for unknown number. Let x be first number .
X+1 To be second number .x+2be third number. X+(x+1)+(x+2)=312.
Simplify to get 3x+3=312 . Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109.then divide 3 both sides . 3x/3=309/3. To get x= 103.
Now once you have that First number 103. Second number 103+1=104 . And third number 103+2=105. To check add them 103+104+105=312
At this point in time, you can use a technique called cross-mutiplication, where you say that
, and
at this point in time, you can devide each side by 8 and solve
<span>8+0.4+0.07+0.008 you basically separate the numbers starting with the largest working down to the smallest.
i hope i helped
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Answer:
924/448
Step-by-step explanation:
7/8×33/8
=231/64
=231/64÷7/4
=231/64×4/7
=924/448
