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3 years ago

State the ex and Y intercepts for the given function and then graph the function 2X-3Y=6

Mathematics

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

a) (3, 0), (0, -2)

b) see below

Step-by-step explanation:

The x-intercept is found by setting y=0 and solving for x:

2x = 6

x = 6/2 = 3 . . . point (3, 0), x-intercept

The y-intercept is found by setting x=0 and solving for y:

-3y = 6

y = 6/-3 = -2 . . . point (0, -2), y-intercept

The graph is the line through these points.

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Davis has 141 figures in his action figure collection. One-third of the figures are sports related. How many of the figures in D

Lelu [443]

We have been given that Davis has 141 figures in his action figure collection. One-third of the figures are sports related.

To find the number of figures that are not sports related we will find 2/3 of 141 as 2/3 of the figures will be not related to sports.

$\text{ Figures not related to sports}=141\times\frac{2}{3}$

$\text{ Figures not related to sports}=47\times2$

$\text{ Figures not related to sports}=94$

Therefore, 94 figures in Davis’ collection are not sports related.

7 0

3 years ago

On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl

kondor19780726 [428]

Answer:

0.40

Step-by-step explanation:

Members who run only long distance = 8%

So, probability that a member will run only long distance = P(A) = 0.08

Members who compete only in field events = 32%

So, probability that a member will compete only in field events = P(B) 0.32

Members who are sprinters = 12%

So, probability that a member is sprinter = P(C) 0.12

We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:

P(A or B) = P(A) + P(B)

Using the values, we get:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40

7 0

3 years ago

Find the unknow side of the right triangle 2. b=73.6 cm b= 19.0

shusha [124]

Assumed 73.6cm is the hypotenuse.

$a^{2} + b^{2} = c^{2}$
$19^{2} + b^{2} = 73.6^{2}$
$b^{2}$ = $73.6^{2} -19^{2}$
$b^{2}$ = $5055.96$
$b$ = $71.1$

Assumed 73.6cm is not the hypotenuse.
$a^{2} + b^{2} = c^{2}$
$19^{2} + 73.6^{2} = c^{2}$
$c^{2}$ = $73.6^{2} +19^{2}$
$c^{2}$ = $5777.96$
$c$ = $76.0$

7 0

3 years ago

I NEED HELP PLEASE, THANKS.

saveliy_v [14]

Answer:

B. $33.7 mm; 54mm^2$