A clock has the diameter of 12 inches. What is the area? asap plz

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

4 0

Answer:

113.04

Step-by-step explanation:

A= πr²

A= (3.14) (6²)

A= (3.14) (36)

A= 113.04

evablogger [386]3 years ago

4 0

Answer: The area is 113 inches squared (approximately)

Step-by-step explanation: If the clock has a diameter of 12 inches, then the radius can be derived as diameter divided by 2. That is,

Radius = diameter/2

Radius = 12/2

Radius = 6

The area of a circle is given as

Area = pi x r^2

Where pi is 3.14 and r is 6,

Area = 3.14 x 6^2

Area = 3.14 x 36

Area = 113.04

Therefore, the area of the clock is approximately 113 inches squared

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ZABD and ZCBD are adjacent. Given that m_ABC is 68º. MZABD= (2x + 5)º, and mZCBD= (3x+8)º, find mZCBD.

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I think that the required options are wrong.

Answer is given below with explanations.

mZCBD = 41 degrees

Step-by-step explanation:

$from \: the \: \: above \: mentioned \: diagram \\ we \: can \: say \: that \: \\( angle \: ABD) + (angle \: DBC) = 68 \\ given \: that \: \: angle \: ABD = 2x + 5 \\ and \: \: angle \: CBD = 3x + 8 \\ on \: substituting \: the \: values \\ (2x + 5) + (3x + 8) = 68 \\ 5x + 13 = 68 \\ 5x = 68 - 13 \\ 5x = 55 \\ x = \frac{55}{5} \\ x = 11 \\ angle \: CBD = 3x + 8 \\ \: \: = 3(11) + 8 \\ \: \: = 33 + 8 \\ \: \: angle \: CBD= 41$