<span>y(1) = 0
y'(1) = e
y" = c1ex + c2e-x
y' = c1ex - c2e-x
for solving c1, 0 = c1e1 + c2e-1
this implies that c1 = - (c2/e2) and
to solve c2
e1 = (-c2e-2)e1 - c2e-1
e1 = (-2c2e-1)
c2= - (e1/2e-1) = - (e2/2)
c1 = - (c2/e2) = (e2/2e2)
Therefore y =(e2/2e2)ex - (e2/2)e-x</span>
Answer:
0.03
Step-by-step explanation:
you move the decimal points two digits to the left
Simply plug in x = 4 in to the function
f(4) = 1/3 * 4
f(4) = 4/3
