Answer: here u go ig
Step-by-step explanation:
Answer:
Step-by-step explanation:
Remark
My guess is that what is confusing you is not what you have to do, but why it is disguised as g(n)
What you are doing in effect is setting up a table. You are also not certain where the table starts. And that is a problem. I will start it at zero, but it might be 1.
zero
n = 0
g(0) = 34 - 5*0
g(0) = 34
One
n = 1
g(1) = 34 - 5*1
g(1) = 34 - 5
g(1) = 29
Two
g(2) = 34 - 5*2
g(2) = 34 - 10
g(2) = 24
Three
g(3) = 34 - 5*3
g(3) = 34 - 15
g(3) = 19
Four
g(4) = 34 - 5*4
g(4) = 34 - 20
g(4) = 19
Answer
0 1 2 3 4
34 29 24 19 14
Let's say, the amount that each side was increased was "a"
so, it was 5 wide and 12 long, now it's 5+a wide and 12+a long
we know the area is 120, so whatever "a" is, we know that
(5+a)(12+a) = 120
so

use those factors, solve for "a"
If we have two numbers A&B and we know that A times B=0 then it must follow that either A=0, or B=0 (or both)
Hello here is a solution :
<span> |x + 2| < 5
-5</span>< x+2<5
-5-2 < x+2-2 <5-2
-7<x<3
<span>interval notation : open (-7) ; open(3)</span>