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2 years ago

Find each variable please!!!

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

8 0

Answer:

x = 6.5

Step-by-step explanation:

By property of intersecting secants outside of circle.

$6(6 + x) = 5(5 + 10) \\ 36 + 6x = 5 \times 15 \\ 6x = 75 - 36 \\ 6x = 39 \\ x = \frac{39}{6} \\ x = \frac{13}{2} \\ x = 6.5$

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Work at the value of 2=3x+5

Alekssandra [29.7K]

Answer:

x = - 1

Step-by-step explanation:

Given

2 = 3x + 5 ( subtract 5 from both sides )

- 3 = 3x ( divide both sides by 3 )

- 1 = x

8 0

2 years ago

Please Help 6-10 or just one of them

Free_Kalibri [48]

Answer:

6) 20

7) I think is 2.5 (im not sure)

8) 7

Step-by-step explanation:

6) (5x+9)+(3x+11)=180

8x+20=180

-20 -20

8x=160

Divide 8 on each side

x=20

7) (17x+1)=(20x-14)

17x+15 =20x

+17 +17

15 = 37x

divide 15 on each side

X=2.5

8) (3x+3)+(10-4)=90

(3x)+(10x-1)

13x-`1=90

+1 +1

13x=91

Divide 13 on each side

x=7

5 0

2 years ago

G(x)=2x-x3+8 polynomial function

KonstantinChe [14]

the answer is 8 G(×) =0 interpret something like that but yeah

4 0

2 years ago

Required information NOTE: This is a multi-part . Once an answer is submitted, you will be unable to return to this part A club

algol13

Answer:

491400

Step-by-step explanation:

Given : A club has 28 members.

To Find : . How many ways are there to choose four members of the club to serve on an executive committee?

Solution:

We are supposed to choose four members of the club out of 28.

So, we will use combination

Formula : $^nC_r=\frac{n!}{r!(n-r)!}$

n = 28

r = 4

Substitute the values :

$^{28}C_{4}=\frac{28!}{4!(28-4)!}$

$^{28}C_{4}=\frac{28 \times 27 \times 26 \times 25 \times 24!}{4!(24)!}$

$^{28}C_{4}=\frac{28 \times 27 \times 26 \times 25 \times 24}{4 \times 3 \times 2 \times 1}$

$^{28}C_{4}=491400$

Hence there are 491400 ways o choose four members of the club to serve on an executive committee

8 0

3 years ago

If f(x) = 16x2 - 20x, what is the value of 13)?

aksik [14]

I don’t get this question right here

6 0

3 years ago