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3 years ago

Find each variable please!!!

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

x = 6.5

Step-by-step explanation:

By property of intersecting secants outside of circle.

$6(6 + x) = 5(5 + 10) \\ 36 + 6x = 5 \times 15 \\ 6x = 75 - 36 \\ 6x = 39 \\ x = \frac{39}{6} \\ x = \frac{13}{2} \\ x = 6.5$

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Which triangles could not be similar to triangle ABC ? triangle a b c with right angle b. side a b is 12 cm. side b c is 5 cm. s

Vera_Pavlovna [14]

Answer:

triangle JKL

Step-by-step explanation:

This is because the lengths of each side JKL is a factor to ABC

respectively .

AB=12,JK=36

AC=13,JL=39

BC=5,KL=25

I hope you understand

6 0

2 years ago

Correct 24.3318 to two decimal places

aliina [53]

24.33 is the answer to this question

4 0

3 years ago

Max built a rectangular Prism and a rectangular Pyramid using beach sand. The prism and the pyramid have the same base area and

vova2212 [387]

Answer:

Three times

Step-by-step explanation:

Given

Figures: Rectangular Prism and Rectangular Pyramid

Let the dimension of the prism be:

$l = length$

$w = width$

$h = height$

Amount of sand used is the volume (V1) and it is calculated using;

$V_1 = l * w * h$

$V_1 = lw h$

Since the pyramid has the same base area and height as the prism, the its dimension would be:

$l = length$

$w = width$

$h = height$

Amount of sand used is the volume (V2) and it is calculated using;

$V_2 = \frac{1}{3}*(lwh)$

So, we have:

$V_1 = lw h$

$V_2 = \frac{1}{3}*(lwh)$

Substitute lwh for V1 in the second equation

$V_2 = \frac{1}{3}V_1$

Multiply both sides by 3

$3 * V_2 = \frac{1}{3}V_1 * 3$

$3 * V_2 = V_1$

Reorder

$V_1 = 3 * V_2$

$V_1 = 3 V_2$

<em>Hence, the amount of sand used in building the prism is three times the amount of sand used in building the pyramid</em>

3 0

3 years ago

The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

$v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}$

When we use this to replace the 't" in the displacement formula, we et:

$y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}$

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)