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2 years ago

PLS HELP ASAP Which number is less? 3/5 OR 0.53

Mathematics

2 answers:

Aleksandr-060686 [28]2 years ago

5 0

Answer:

0.53

Step-by-step explanation:

kotykmax [81]2 years ago

3 0

Answer:

0.53

Step-by-step explanation:

53/100<60/100

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5 − c = –11 c = ? What is C? Please help! I'll give brainliest

jonny [76]

Answer:

Step-by-step explanation:

you would get c alone so you subtract 5 to the other side

4 0

3 years ago

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Find the median of the data. 24,74,61,29,38,27,68,54

Nataly_w [17]

Answer:

The median of the data is 46.

Step-by-step explanation:

Put the numbers in order so it would look like this.

24, 27, 29, 38, 54, 61, 68, 74

The ones in the middle would be the mean, however, there are two numbers in an even-number data, 38 and 54.

Add these two numbers together to get 92 and divide that number by 2 to get your median which is 46.

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3 years ago

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Ms. Morgan is the cafeteria manager. She keeps track of how many students select each type of drink. Today during breakfast, 32

blsea [12.9K]

Answer:

ratio of those who picked juice to milk

it refers to division

6 0

1 year ago

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

Write the equation in standard form. x + y = 6y

Igoryamba

$x + y = 6y$

Subtract the sides of the equation minus 6y

$x + y - 6y = 0$

$x - 5y = 0$

$- 5y + x = 0$

$a = - 5$

$b = 1$

$c = 0$

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

5 0

3 years ago