Help pleaseeeee!!!!!

C=-4 D=5 P=2 Q=-1 4cd×10×2p÷50d+20q=??

nata0808 [166]

This is very simple; don't you worry.
Let's start by breaking down the problem so that it's not overwhelming.
For now, we're only going to focus on the very beginning of the problem -- 4c.
When a number is next to a letter with no signs in between (in terms of this kind of math), the number is called a coefficient and the letter is called a variable. When you see this in math, it means that the coefficient is being multiplied by the variable. But how do you know what the variable is?
In other examples of math, you'd have to solve for the variable, but in this case, they already give it to you! Look back at the top... what does C equal? It equals 4! This means that 4c is actually 4x4, or 4(4)!
What we just did there, changing 4c to 4 multiplied by 4, is called substitution. You just substituted the c with 4. Now you know that to solve this, you need to use the method of substitution. What do you get if you substitute all of the variables with the numbers they equal (as shown above)...?

((4*-4)*5)((10(2*2))/(50(5)))+20(-1). You didn't use parentheses to separate the term /50d + 20q, so I'm assuming that the first part of the problem is only divided by just 50d, and not 50d+20q. In the future, be sure to clarify with parentheses. Anyway...
((4*-4)*5)((10(2*2))/(50(5)))+20(-1). Do NOT let this scare you. All the parentheses do is help you see what is being multiplied. All that's left is simple order of operations! You should get -340 as your answer.

7 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

What's the value of x and y?

krok68 [10]

Answer:

x = 45 and y = 90

Step-by-step explanation:

Let the third angle be z

z = 180 - 135 (Linear Pair)

z = 45

Since its an iscosceles triangle,

<z = <x (angles opposite to equal sides have equal angles)

<x = 45 degree

<z + <x + <y = 180

45 + 45+ <y = 180

90 + <y = 180

<y = 180 - 90

<y = 90

Therefore x = 45 and y = 90

Hope u understood please mark as brainliest

Thank You

6 0

2 years ago

Read 2 more answers

When Romano win out with her three sisters I spent 58+9% tax on the meal they are solar 15% to a very divided it up the bill eve

umka21 [38]

Answer:

I'm not sure what the answer you are looking for is but if it is 58 + 9%, plus 15% more, that would be 72.703

8 0

2 years ago

PLEASE HELP ———————-

quester [9]

First substitute, then distribute, then add, then simply

5 0

3 years ago