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2 years ago

14

The area of a rectangular garden is 6862 m².

1 answer:

blsea [12.9K]2 years ago

6 0

The length of the rectangle would be 94m.

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Graph the system of equations on your graph paper to answer the question. {y=−x+4y=x−2

Rudik [331]

This is the graph that I drew to figure out the answer to this question.

3 0

3 years ago

Evaluate the following expression:<br> 62 − 7(8 + 6 − 32)

Alex Ar [27]

Answer:

188

Step-by-step explanation:

<u>Step 1: Distribute</u>

62 − 7(8 + 6 − 32)

62 + (-7 * 8) + (-7 * 6) + (-7 * -32)

62 + (-56) + (-42) + (224)

<u>Step 2: Combine the first two numbers</u>

(62 - 56) - 42 + 224

6 - 42 + 224

<u>Step 3: Combine the next two number</u>

(6 - 42) + 224

-36 + 224

<u>Step 4: Combine the last two number</u>

-36 + 224

188

Answer: 188

3 0

3 years ago

The graphs of the equations Ax + By =15 and Ax - By =9 intersect at (2, 1). Find A and B. Show or explain your reasoning

iVinArrow [24]

Hi here’s the answers hope this helps

5 0

3 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

How do you find degree measures? How would you solve this question?

MrRa [10]

A. a=145 b=35 c=145 d=145 e=35 f=145 g=35

b. These are the pairs of vertical angles: a & c, b & 35, d & f, e & g.

Hope this was helpful.

8 0

2 years ago