Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Cut the figure into two parts
area of a rectangle is length x width
10x5=50m
2x4=8
add them together
50+8=58
Answer:
$9,769.60
Step-by-step explanation:
A = 8000[1 + (.02/12)]^12·10
Answer:
2(x + y)
Step-by-step explanation:
You can pull out a 2 from the expression.
So divide 2x by 2 and 2y by 2.
2x/2 = x
2y/2 = y
2(x + y)
Two angles are supplementary when they <span>add up to 180 degrees </span>⇒
m∠1 + m∠2 = 180°
4y + 7 + 9y + 4 = 180
13y + 11 = 180
13y = 180 - 11
13y = 169
y = 169/13
y = 13
m∠2 = 9y + 4 = 9 * 13 + 4 = 121°
