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mina [271]
2 years ago
14

(4 ⅓)C - (8/6)C +12 = 6plz help me

Mathematics
2 answers:
shutvik [7]2 years ago
6 0

Answer:

e3xeh2fszwreswkxzwa

Step-by-step explanation:

grewgqdxqrbjgsnu2ay

aleksley [76]2 years ago
6 0
C=-2 is your answer I am certain
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The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

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