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2 years ago

Help me fast

Mathematics

1 answer:

Dmitry [639]2 years ago

7 0

Y= x2+2 is the correct answer

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Please help me with this sum

Maslowich

Answer:

6327

1827

2418

832

742

606

3248

2127

5436

203 X 4=812

Step-by-step explanation:

4 0

2 years ago

What is the area of the figure below?

murzikaleks [220]

96m^2 is your answer

6 0

3 years ago

Read 2 more answers

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

Viktor [21]

The given equations satisfy the given conditions. There are 2 equations and 2 unknowns, so a certain solution can be found.

This can be solved using substitution,

Substituting eqn 2 to eqn 1:

2(2y – 10) + 3y =1240

Simplifying,

y = 180

x = 350

7 0

3 years ago

Imension

kipiarov [429]

Answer:

sorry can we have more info?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

4 0

3 years ago