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hammer [34]
3 years ago
15

Jenny collects seashells and interesting rocks. She keeps her collections in boxes shaped like rectangular prisms. Her seashell

box is 5 inches tall and has a volume of 200 cubic inches. Her rock box has a volume of 280 cubic inches. The area of the base of both boxes is the same. How tall is Jenny's rock box?
Mathematics
1 answer:
algol [13]3 years ago
3 0

Answer:

7 in

Step-by-step explanation:

volume of a rectangular prism = width x height x length

width x length = area of the base

the sea shell box

200 = width x length x 5

width x length = 200/5 = 40cm^2

rock box

280 = 40in^2 x height

height = 280/40 = 7 in

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Find the value of f(-6).<br><br> y = f(x)<br><br><br> Please help
Gala2k [10]

Answer:

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The question is asking what the output is when you input -6 for x. You get the point (-6,4)

7 0
3 years ago
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

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b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

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c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

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The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
3 years ago
I need to know the answer please help me
spin [16.1K]
First is 42 and the second is 4.5
6 0
2 years ago
Help would be very helpful :) the answers are: (812pi cm^3) (602pi cm^3) (735 cm^3) and (512pi cm^3) 30 points!!!!!
g100num [7]

Find the area of the top ( circle) then multiply by the height.

Area = pi x r^2

Area = pi x 7^2

Area = 49pi

Volume = 49pi x 15

Volume = 735pi cubic cm.

6 0
3 years ago
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