1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
6

Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.

Discuss whether the approximation technique worked a. 31.000 x 200 b. 6.2 thousand x 5.2 million c. 9,000,000 - 23,000 a. The approximate value of 31,000 x 200 is 6x 10 The exact value of 31,000 x 200 is (Use scientific notation. Use the multiplication symbol in the math palette as needed.) * : * More Enter your answer in the answer box and then click Check Answer 7 Parts Clear All Check Answer remaining
Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

You might be interested in
Please can you help me I don't understand
Alexxx [7]
I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)

1.)  20yx , 80x³  ( factor each number and variable)

20  =  2, 4, 5, 10, 20
y    =  y
x     =  x
80  =  2, 4, 5, 8, 10, 16, 20, 40, 80
x³  =  x, x, x

what is the largest number that 20 and 80 have in common?    20...
how about the variables?    x

so, the Greatest Common Factor (GCF is 20x)
8 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
2 years ago
Olhe a imagem e responda
matrenka [14]

Answer:

i cant see the attachment

8 0
3 years ago
Is it true or false that 16.371 rounded to the nearest whole number 16 feet per second
rusak2 [61]

Answer:

true

Step-by-step explanation:

To round off a number to its nearest whole number, look at the first number after the decimal point. If the number is equal or greater than 5, add 1 to the number before the decimal point. If it is  less than 5, add zero.

Because the first number after the decimal point is 3, which is less than 5, add zero to 16 . 16 + 0 = 16

If the number were 16.571, rounding off to the nearest whole number would give 17

4 0
3 years ago
The height of a trapezoid is 15m and the midsegment is 32m. What is the area of the trapezoid?
viktelen [127]
The formula is: A=1/2 h (base one + base two) 

<span>Plug in your numbers and you will get the area.</span>
6 0
3 years ago
Other questions:
  • Write the number in standard form 12 ten thousand 8 thousands 14 hundreds 7 ones
    13·2 answers
  • PLEASE ANSWER I NEED DONE
    6·2 answers
  • Square 1 has a side length of x, and square 2 has a side length of y. Square 2 is formed by joining the midpoints of the sides o
    11·2 answers
  • Please help me with this math problem Plzz<br> see the picture.
    9·1 answer
  • 24 is 75%, percent of what number?
    12·1 answer
  • Your parents love coffee . They purchased a bag of coffee online for 10.99. Since they purchased it online . They received 18% o
    12·1 answer
  • Does anybody get this and if you do help a brother out man:))
    7·1 answer
  • Help me with this math question please I'm giving away brainliests​
    13·2 answers
  • N-
    5·1 answer
  • PLEASE HELP! Let f(x)= 6x+1 find f(a) + f(2)
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!