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Paladinen [302]
2 years ago
11

Write the explicit formula for the sequence. 27, 18, 12, 8,.... A) an = 9(2/3)(n-1) B) an = 27(3/2)(n-1) C) an = 27(1/3)(n-1) D)

an = 27(2/3)(n-1)
Mathematics
1 answer:
Nikitich [7]2 years ago
5 0

Answer: A

Step-by-step explanation:

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Given that MN = 5, NO = 12, and MO = 13, find cos O.
Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0
3 years ago
Find the area of the shaded portion in the equilateral triangle with sides 6.
LUCKY_DIMON [66]
Triangle is equilateral with sides of 6.
Therefore all angles = 60°
Ht of 30-60-90 is 3sr3 = 5.196
Area of 30-60-90 = 1/2×b×h = 3×5.196
Area = 15.59
Pie slice from each corner = 60/360×pi×r^2, with r = 3
1/6×pi×9 = 4.71 × 3 pie slices = 14.13
So, shaded inner region = area triangle - 3 pie corners = 15.59-14.13
= 1.46
7 0
2 years ago
I NEED AN ANSWER ASAP!! IM MARKING THE FIRST ANSWER BRAINLIEST!
Rom4ik [11]
The tennis balls will not go the same distance

Hope this helps :D

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3 0
2 years ago
Please help differentiate this!!!!!!!!!
vlada-n [284]
\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t

\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3  \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}
5 0
3 years ago
Read 2 more answers
How can you tell from the scale factor whether the original figure was enlarged or reduced?
Stels [109]

If the scale factor is less then 1, it was reduced.

If the scale factor is more than 1, it was enlarged.

If it is equal to 1, it is the same.

Hope this helps!

8 0
3 years ago
Read 2 more answers
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