Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
1

because 36 goes into 60 1 time with 24 left over
Answer:
The container is filled to 87.5% of the maximum capacity.
Step-by-step explanation:
Given
Maximum capacity of container = m = 64 ounces
Filled capacity=> as it is 8 less than maximum capacity = 64-8 = 56 ounces
The container is 56 ounces full.
To find the percentage:

Hence,
The container is filled to 87.5% of the maximum capacity.
Answer:
23
Step-by-step explanation:
Evaluate f(- 2) then substitute the value obtained into g(x)
f(- 2) = 3(- 2)² + 2(- 2) - 1 = 3(4) - 4 - 1 = 12 - 5 = 7 , then
g(7) = 4(7) - 5 = 28 - 5 = 23