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2 years ago

Helpppp plssss anyoneeee

Mathematics

1 answer:

____ [38]2 years ago

3 0

Answer:

1.25

Step-by-step explanation:

that was my answer!!!

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Plz help I'm stuck and thx for everyone who helps me

iVinArrow [24]

White has the highest probability.<span />

5 0

3 years ago

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(8/9)^-2 without an exponent

Ganezh [65]

Answer:

81/64 or 1 17/64

Step-by-step explanation:

A negative exponent means to flip the fraction

(8/9) ^-2

(9/8)^2

81/64

Changing this to a mixed number

1 17/64

8 0

3 years ago

Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f

GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that $p = \frac{3}{4} = 0.75$

Giannis shoots three free throws

This means that $n = 3$

What is the probability that he succeeds on at least two of them

$P(X \geq 2) = P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219$

$P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219$

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438$

84.38% probability that he succeeds on at least two of them

6 0

2 years ago

What's 18 divided by 5634❤️Pls help

White raven [17]

It's approximately 0.0032

4 0

3 years ago

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What does it mean when there are variables on top of each other in parentheses in statistics?

Ilya [14]

It's a combination:
$\left( {{n} \atop {k}}\right)\equiv C(n,k)=\dfrac{n!}{(n-k)!k!}$

4 0

2 years ago