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serious [3.7K]
3 years ago
12

Which equation represents the sentence?

Mathematics
2 answers:
djyliett [7]3 years ago
5 0
I think it's the first one
Sveta_85 [38]3 years ago
3 0

Answer:

<u><em>N - 8= N/3</em></u>

Step-by-step explanation:

<u><em>JUST TOOK THE TEST </em></u>

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2 years ago
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The expression (3z2) (2z4) is equivalent to which of the following numerical expression? A. 6z8 B. 6z6 C. 5z6 D. 5z8
balandron [24]
B.6z6
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3 years ago
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There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
3 years ago
The Orchard Cafe has found that about 3% of the diners who make reservations don't show up. If 83 reservations have been made, h
daser333 [38]

Answer:

\mu = 80.51\\\sigma = 1.56

Step-by-step explanation:

We are given the following information in the question:

Percentage of of the diners who make reservations don't show up = 3%

Number of reservations = 83

Thus, we are given a binomial distribution with n = 83 and p = 0.97

X\sim \text{ Binom}(p = 0.97, n = 83)

\mu = np = (83)(0.97) = 80.51

Around 81 people  can be expected to show up.

\sigma = \sqrt{np(1-p)} = \sqrt{(83)(0.97)(1-0.97)} = 1.5541 \approx 1.56

The standard deviation of this distribution is 1.56

6 0
3 years ago
i ran 3hrs and 2 mins to run 26 miles if i ran at the same rate for the whole race how many minutes did it take to run each mile
oksian1 [2.3K]
7 minutes per mile.
8.57 miles per hour
8 0
3 years ago
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