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3 years ago

Hi I really need this question answered use the screenshot

Mathematics

1 answer:

ladessa [460]3 years ago

5 0

Answer:

The picture is at the bottom

Step-by-step explanation:

Here are all of the angles:

use these rules:

-the diagonals bisect the angles they cut into

- the diagonals form a 90 degree angle with each other

- the interior angles of a triangle add up to 180 degrees

- the opposite angles of a smaller where the smaller diagonals are, are equal

- the total angles of a quadrilateral is 360 degrees

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A potter is creating a design for a red-colored urn. He starts with the design shown on the coordinate grid.

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Hey, you would have to change your points if you want this done. It’s not worth 5 points.

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3 years ago

which type of angle pair are 1.) Obtuse <br> 2.) Linear pair<br> 3.) Complementary angles <br> 4.) Vertical angles

julia-pushkina [17]

Answer:

Step-by-step explanation:

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3 years ago

Find the area of this triangle

Dahasolnce [82]

A. 48 is the answer because 8x6

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3 years ago

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Please help me to solve this . Thank you so much .

worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

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4 years ago

Which statement correctly compares the constants of variation for the graph and the equation below?

Lynna [10]

Answer:

The equation has a greater constant of variation

Step-by-step explanation:

The graph is of a line through point (0, 0) can be represented by the equation ...

y = kx

Using the given values for x and y, we see that ...

3 = k·1

k = 3 . . . . . the constant of variation for the graph

The given fraction can be rewritten as ...

y = (10/3)x = (3 1/3)x

In this form, the constant of variation is 3 1/3, greater than that of the graph.

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3 years ago

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