Find the area of this triangle

Mathematics

2 answers:

Dahasolnce [82]3 years ago

6 0

A. 48 is the answer because 8x6

blondinia [14]3 years ago

3 0

Answer:

Step-by-step explanation:

multiply the hieght by the base you will get 56 then divide it by 2

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9) 4 = K/42 Solve that for me pls I’m writing here because I need twenty words

DaniilM [7]

Answer:

k = 168

Step-by-step explanation:

$4= \frac{k}{42}$ rewrite the equation

$42 * 4=\frac{k}{42} *42$ Multiply 42 to isolate k. Do the same on the other side

42 * 4 = 168 When you do that you get 168.

8 0

3 years ago

Find the slope of the line that passes through each pair of points. Expressed as a fraction in simplest form. (8,2),(8,-1)

boyakko [2]

Answer:

x = 8

Step-by-step explanation:

The explanation are the pictures. I hope I gave you the correct answer.

8 0

2 years ago

For what value of c is the function defined below continuous on (-\infty,\infty)?

kozerog [31]

$f(x)= \left \{ {{x^2-c^2,x \ \textless \ 4} \atop {cx+20},x \geq 4} \right
$

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
A function, f, is continuous at x = 4 if
 $\lim_{x \rightarrow 4} \ f(x) = f(4)$

In notation we write respectively
 $\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)$

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just 4c + 20.

On the other hand, for x < 4, f(x) = x^2 - c^2. Hence
$\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2$

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c²

$c^2+4c+4=0
\\(c+2)^2=0
\\c=-2$

That is to say, if c = -2, f(x) is continuous at x = 4.

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers $(-\infty, +\infty)$