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valina [46]
3 years ago
11

Evaluate y = [X + 1] at x = 3.001?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer: 4

Step-by-step explanation:

Given

y=[x+1]

where, [  ]=Greatest integer function

Put x=3.001

\Rightarrow y=[3.001+1]=[4.001]\\\Rightarrow y=[4+0.001]=4

Thus, the value of y is 4

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See attachment for options

Required

True statement about the graph

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y = 2(x^2 - 2x + 1) - 5

Open bracket

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