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Sophie [7]
3 years ago
8

(-5) -2-8 + 11-5-2-8helpp plisssssss ​

Mathematics
2 answers:
Hoochie [10]3 years ago
5 0

Answer:

-14

Step-by-step explanation:

(-5)-2-8+1

-5-2-8+1

-7-8+1

-15+1

-14

Dafna11 [192]3 years ago
5 0

Answer:

-14

Step-by-step explanation:

Using my ctrl+c and ctrl+v skills, I have come to the conclusion that...

1 - 5 - 2 - 8 = -14

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stiv31 [10]

Answer:

a. x<3

b. 3,4,5,6

c.x>6

8 0
3 years ago
What is the surface area of the square pyramid
In-s [12.5K]

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16 ft

Step-by-step explanation:

3 0
3 years ago
Rebecca solved
Nuetrik [128]

No.

\sqrt{45}=3\sqrt{5}  \\2\sqrt{20} =2\sqrt5}

If you add them up you DO NOT GET 5\sqrt{5}. According to mathematics, it equals to 7\sqrt{5}.

8 0
3 years ago
Select the correct answer from each drop-down menu. A system of equations and its solution are given system A x-y=7 -3x+9y=-39 s
galina1969 [7]

Answer:

Step-by-step explanation:

x-y=7

-3x+9y=-39

Divide the second equation by 3

-x +3y = -13

Add this to the first equation

x-y=7

-x +3y = -13

----------------------

0x +2y = -6

Divide by 2

2y/2 = -6/2

y = -3

Now find x

x-y = 7

x -(-3) = 7

x+3 = 7

Subtract 3 from each side

x = 4

(4,-3)

Or by substitution

x-y=7  

solve for x

x = 7+y

-3x+9y=-39

Substitute y+7 in for x

-3(7+y) +9y = -39

Distribute

-21 -3y +9y = -39

Combine like terms

-21 +6y = -39

Add 21 to each side

6y = -18

4 0
2 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7291

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have s = 5, n = 20. So

M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0
3 years ago
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