All categories

3 years ago

(-5) -2-8 + 11-5-2-8helpp plisssssss

Mathematics

2 answers:

Hoochie [10]3 years ago

5 0

Answer:

-14

Step-by-step explanation:

(-5)-2-8+1

-5-2-8+1

-7-8+1

-15+1

-14

Dafna11 [192]3 years ago

5 0

Answer:

-14

Step-by-step explanation:

Using my ctrl+c and ctrl+v skills, I have come to the conclusion that...

1 - 5 - 2 - 8 = -14

You might be interested in

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

$\frac{1}{3}=e^{-0.05t}$

Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

3 years ago

Average speed of Car 1 = 35 mph. Average speed of Car 2 = 55 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 mi

gizmo_the_mogwai [7]

It is 0.53 hope this helps you.

7 0

3 years ago

Read 2 more answers

A bag contains 3 gold marbles, 9 silver marbles, and 20 black marbles. Someone offers to play this game: You randomly select one

Genrish500 [490]

What’s the question?

3 0

2 years ago

The point R(-3,a,-1) is the midpoint of the line segment jointing the points P(1,2,b)

wlad13 [49]

Answer:

The values are:

$a = -5/2$

$b = -6$

$c = -7$

Step-by-step explanation:

Given:

P = (x₁, y₁, z₁) = (1, 2, b)

Q = (x₂, y₂, z₂) = (c, -7, 4)

m = R = (x, y, z) = (-3, a, -1)

To Determine:

a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b) and Q(c,-7,4), so

m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

given

(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

m = (x, y, z) = (-3, a, -1) = R

substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P, (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

$\left(x,\:y,\:z\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

as (x, y, z) = (-3, a, -1), so

$\left(-3,\:a,\:-1\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

Determining 'c'

-3 = (1+c) / (2)

-3 × 2 = 1+c

$1+c = -6$

$c = -6 - 1$

$c = -7$

Determining 'a'

a = (2+(-7)) / 2

$2a = 2-7$

$2a = -5$

$a = -5/2$

Determining 'b'

-1 = (b+4) / 2

$-2 = b+4$

$b = -2-4$

$b = -6$

Therefore, the values are:

$a = -5/2$

$b = -6$

$c = -7$

6 0

3 years ago

Suppose you had d dollars in your bank account. You spent $21 but have at least $53 left. How much money did you have initially?

likoan [24]

D-21≥ 53 hope this helps

6 0

3 years ago

Read 2 more answers

(-5) -2-8 + 11-5-2-8helpp plisssssss ​

(-5) -2-8 + 11-5-2-8helpp plisssssss