3 years ago

ANSWER THIS AND ILL LOVE YOU find angles FAB and BAC

Mathematics

1 answer:

jeyben [28]3 years ago

4 0

Answer:

m<FAB = 75°

m<BAC = 105°

Step-by-step explanation:

First, find the value of x.

(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)

Solve for x

13x - 3 = 3x + 2 + 55

13x - 3 = 3x + 57

Collect like terms

13x - 3x = 57 + 3

10x = 60

Divide both sides by 10

x = 6

✔️m<FAB = 13x - 3

Plug in the value of x

m<FAB = 13(6) - 3 = 78 - 3

m<FAB = 75°

✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)

m<BAC = 180 - 75 (substitution)

m<BAC = 105°

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