Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;
![\frac{x-733}{9}=1.645](https://tex.z-dn.net/?f=%5Cfrac%7Bx-733%7D%7B9%7D%3D1.645)
![{x-733}}=1.645\times 9](https://tex.z-dn.net/?f=%7Bx-733%7D%7D%3D1.645%5Ctimes%209)
![x = 733 + 14.81](https://tex.z-dn.net/?f=x%20%3D%20733%20%2B%2014.81)
x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Green Line:
This is a horizontal line at x = 0, so it would be:
x ? 0
Since the shaded area is going to the left of 0 (this means x is negative):
x ≤ 0
Blue Line:
The shaded area is below the line, so:
y ≤ mx + b
When x = 0, y is -5.
y ≤ mx - 5
From each point, you go up 3 units, and to the right 4 units, so the slope is
.
![y\leq \frac{3}{4}x-5](https://tex.z-dn.net/?f=y%5Cleq%20%5Cfrac%7B3%7D%7B4%7Dx-5)
Answer:
I think it is the first one.
Step-by-step explanation:
I think that becuase it is equal.
Answer: x = -8
Step-by-step explanation: 2x=-16, x=-8
Answer:
it is 18:12
Step-by-step explanation:
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