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3 years ago

15

Jason built a model of the Pentagon for a social studies project. He made each outside wall 33 centimeters long. What is the per

imeter of Jason’s model pentagon?

1 answer:

sammy [17]3 years ago

8 0

Answer:

165 centimeters

Step-by-step explanation:

A pentagon has 5 sides

Each side is 33 centimeters long

5 x 33 = 165

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MA_775_DIABLO [31]

<em>Answer: C</em>

<em />

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<em>It is C because when there is a line at the top of the number, it is infinite and repeats many times. That number in a shorter was can be written as a fraction over 990. Two of the answer choices has 990 in it which is letters B and C. This eliminates answer choices A and D. The number that is within the dot is your numerator (645) and 990 is your denominator. Overall the answer is 645/990</em>

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Solve the absolute value equation or indicate that the equation has no solution.|2x - 3= 7Select the correct choice below and, i

Whitepunk [10]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

In the question, we are looking at the absolute value function which says that:

Based on this, we have that:

$undefined$

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1 year ago

Which of the following are solutions to the equation below ?

Ad libitum [116K]

The equation factors into (x+2)(x+6) = 0. The answers to this question are -2 and -6.

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3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

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tankabanditka [31]

Answer:

C

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